How can I programmatically enable and disable Extras?

Photoshop UXP Plugin API
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2

in my search I couldn’t find a way to set the checked value of a menu item so I went with 2nd best thing.

I get the current state of the menu item and and toggle only if needed.

async function showExtras(state){
    let extrasIsChecked = (await batchPlay([{
        "_obj": "get",
        "_target": [{"_property": "menuBarInfo"},{"_ref": "application", "_enum": "ordinal", "_value": "targetEnum"},]
    }], {}))[0].menuBarInfo.submenu.find( m => m.name == "View").submenu.find( m => m.name == "Extras").checked
    if (extrasIsChecked != state) {
        await core.performMenuCommand({commandID: 3500})
    }
}

that function can be used as follows:

//Show Extras
await showExtras(true);

//Hide Extras
await showExtras(false);

EDIT:
as pointed out the previous function may fail on non English versions of PS, so here’s another way using IDs instead of names:

async function showExtras(state){
    let extrasIsChecked = (await batchPlay([{
        "_obj": "get",
        "_target": [{"_property": "menuBarInfo"},{"_ref": "application", "_enum": "ordinal", "_value": "targetEnum"},]
    }], {}))[0].menuBarInfo.submenu.find( m => m.menuID== 9).submenu.find( m => m.command == 3500).checked
    if (extrasIsChecked != state) {
        await core.performMenuCommand({commandID: 3500})
    }
}